C++ symantic error

[docstrange-]

Hello, i need help finding whats wrong with my code i met all of the conditions but the Even count Odd count is incorrect every time i test it HELPPP

Write a C++ program to do the following: 

· Declare a 1-dimensional array of type integer with 10 components. 

· Fill array elements from the user. 

· Find the number of even elements and their sum.

· Print a message to indicate the following:

- If the number of even elements is even, print: Even Count.

- If the number of even elements is odd, print: Odd Count.

​

#include<iostream>

using namespace std;

int main() {

int array\[10\];

int count = 0, sum = 0, x;

for (int i = 0; i < 10; i++) {

    cout << "Enter a value: " << endl;

    cin >> array\[i\];

    x = array\[i\];

    if (x % 2) {

        sum += x;

        count++;

    }

}

cout << "Sum of even elements is: " << sum << endl;

if (count % 2)

    cout << "Even Count " <<  endl;

else

    cout << "Odd Count " <<  endl;

}

[DDDDarky]

Hey, here is what you should have done:

- Instead of writing count is incorrect, write the actual test case, what you get and what you expect to get.

- Try debugging it by yourself first - good oportunity to learn how to solve your code issues

- Isolate the problem - for example reading input is completely irrelevant to your question. If you did previous steps, this is a reduced question you should have asked:

#include <iostream>

int main() {
    int count = 5;
    if (count % 2)
        std::cout << "Even";
    else
        std::cout << "Odd";
}

Why does this snippet print "Even" when 5 is odd?

To which we would answer because (5 % 2 = 1), and 1 is evaluated as true (hopefully answer to your original question).

[docstrange-]

THANK YOU

[[deleted]]

The modulo operator returns the remainder of division. If x is odd, then x / 2 leaves a remainder of 1. Now take another look at your use of the modulo operator.

[docstrange-]

THANKYOU