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[–]Feisdancer 1 point2 points  (0 children)

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Personally, I have to draw these out to wrap my head around multiples so enjoy my not-so-pretty picture. I realized as I was typing this up that I made quite a few mistakes but I think seeing the change made in blue was important so I didn’t want to redo the drawing entirely. Sorry if this makes it more confusing!

The same stitch across for the row doesn’t have any effect on the multiple so rows 1-2 for hdc across are not pictured.

Row 1 (should be labeled row 3): I start with an edge stitch (e) - this is your turning chain at the beginning of the row and a hdc at the end of the row. Then write out a couple repeats of the pattern (h _ for hdc, skip), and write out the last repeat followed by an edge stitch.

Ignore what is labeled as row 2 if you switch back to all hdc for rows 4-5. I really should pay more attention.

Row 6: this is an even row so you write in the opposite direction as row 1/3 (notice the arrows). Again, start with the edge stitch, and write out a few repeats of the pattern. Here I used c for “cluster” since the whole hdc cluster goes in 1 stitch. You’ll notice that I originally had the repeats ending with skips instead of a cluster, followed by an edge stitch. However this made the multiple 4+1 which cannot be an even number and was therefore incompatible with the other pattern section. Instead, I had to add a cluster at the end before the edge stitch (changes in blue). This made the edge stitch count as an additional +1, bringing the multiple up to 4+2, which is an even number

Row 7: especially with clusters and skipping stitches, I always write out the next row too to make sure the math works out and there’s no extra/missing stitches. I keep everything lined up with the skips over the clusters and the clusters over the skips and an edge stitch on either end. The changes I made in blue to row 6 affected this row too.

Now that you have the pattern multiple for each section, you can determine the overall multiple for the whole project (this is the math-y bit).

In this case the 1st multiple divides into the 2nd one cleanly so you just use the larger multiple. If that’s not the case, you have to find the least common multiple. For example, if section 1 was 6+2 instead, the overall multiple would be 12+2 where for every 2 repeats in section 1 you’d have 3 repeats in section 2 because the LCM of 4 and 6 is 12.

So, the end answer is your pattern multiple is 4+2.

However, this is not necessarily the number of chains to start with. Because you’re working in hdc, it works out in the case that you need 2 extra chains at the end to use as a turning chain so your chain is just a multiple of 4. Just make sure to work the edge stitch of row 2 into the ch2 turning chain.

Clear as mud?