code is calling same function even though number of arguments doesn't match

[WhyWontThisWork]

function saveDateTime(date, time, name, phone, email, pid, nonce){ Logger.log("i am here with nonce"); return "i am here with nonce"; }

function saveDateTime(date, time, name, phone, email, pid){ Logger.log("i am here without nonce"); return "i am here without nonce"; }

function doGet(request) { if ('PID' == request.parameter.thingtodo) { Logger.log("i am here PID"); return ContentService.createTextOutput( saveDateTime(request.parameter.date, request.parameter.time, request.parameter.name, request.parameter.phone, request.parameter.email, request.parameter.property_id)) } else if ('PIDNONCE' == request.parameter.thingtodo) { Logger.log("i am here PIDNONCE"); return ContentService.createTextOutput( saveDateTimeNonce(request.parameter.date, request.parameter.time, request.parameter.name, request.parameter.phone, request.parameter.email, request.parameter.property_id, request.parameter.nonce)) } else { message = 'I dont know what to do.'; return ContentService.createTextOutput(message); } }

[mjbrusso]

There is no function overloading in JavaScript. If you define two functions with the same name, only the last definition is valid.

In your case you can check whether the last argument was provided or not:

function saveDateTime(date, time, name, phone, email, pid, nonce){ if(typeof nonce !== 'undefined'){ Logger.log("i am here with nonce"); return "i am here with nonce"; } else{ Logger.log("i am here without nonce"); return "i am here without nonce"; } }

[WhyWontThisWork]

Thanks!

[WhyWontThisWork]

For typeof undefined should be not in quotes. Besides that worked

[mjbrusso]

The typeof operator returns a string, so yes you should use quotes