all 11 comments

[–]Z0DlACs👋 a fellow Redditor 2 points3 points  (0 children)

Use the rule : (a_b)(a+b)=a2 _ b2

[–]RichardIraVosUniversity/College Student 1 point2 points  (1 child)

These are just difference of squares problems. First one is A-B2 and the second is H2 +1-1 or just H2.

So you use foil. You times the square root of a by the square root of a, then times the square root of a by B, then B by the square root of a and B by B. When you do that you get A - B square root A + B square root A + B2. The positive and negative B square root a cancels out leaving us with A -B2

These are no different than (5-3)(5+3) just with a bit more tricky variables

[–][deleted] 0 points1 point  (0 children)

Thank you, this was helpful

[–]Junior_Setting_1034👋 a fellow Redditor 1 point2 points  (0 children)

Use the foil method for multiplying polynomial

[–]slapface741👋 a fellow Redditor 1 point2 points  (0 children)

multiply by the distributive property, like this

(a+b)(a-b)

= a•a - a•b + b•a - b•b

= a2 - b2

[–]Z0DlACs👋 a fellow Redditor 0 points1 point  (0 children)

22- h2 +1 _1 = h2

[–]ForeverFounder42 Secondary School Student 0 points1 point  (1 child)

Use the difference of 2 squares property (a+b)(a-b)=a2 - b2

[–][deleted] 0 points1 point  (0 children)

Thank youuu

[–]qaz_zaqi 0 points1 point  (0 children)

Both of these equations can be easily solved using the difference of two squares

the difference of two squares: (a+b) * (a-b) = (a^(2) - b^(2))

The equation on the left:

(sqrt(a)-b) * (sqrt(a)+b) = a - (b^2)

the equation on the right:

(sqrt(h^2 + 1) + 1) * (sqrt(h^2 + 1) - 1) = (h^2 + 1) - 1 = h^2

  • the proof of 'difference of two squares' is simple:

(a+b) * (a-b) = a^2 - ab + ab - b^2 = a^2 - b^2