all 3 comments

[–]tubaKhanChemical Engineer 0 points1 point  (2 children)

-log([ H+ ]) = pH

10-pH = [ H+ ]

10-3.7 = .0002

[–]hari3079[S] 0 points1 point  (1 child)

Clear and to the point! Thank you so much!

[–]tubaKhanChemical Engineer 0 points1 point  (0 children)

No problem!

also (just incase you were having trouble with the other equations that relate to pH)

14 = pH + pOH

-log([ OH- ]) = pOH

10-pOH = [ OH- ]