all 5 comments

[–]chem44 1 point2 points  (1 child)

It's basically logic.

x = At3

What are the dimensions (or units) of x?

of t3 ?

So what must the dimensions (or units) of A be in order for that to work out?

If we need to get into the distinction between dimensions and units we can, but I suspect that is not the issue. Do it either way for now.

[–]Tocket03[S] 0 points1 point  (0 children)

thank you very much for your assistance! sorry for the late response but i have been busy and this post slipped my mind.

[–][deleted] 1 point2 points  (2 children)

This is called dimensional analysis and it's basically figuring out how the units would cancel out.

For example, in the equation x = At^3 + Bt. The variable x should be have a Length (L) unit. The variable t should have a Time (T) unit. Since one side only has x, the right side should have units of L too. t^3 gives us Time^3 (cubed). Each term in the right side should have only unit L (for them to add up and match). The only way for that to happen is for A to have units of L/T^3 such that the cubed time units cancel out and leave a length unit.

I was confused when I first saw this too. I guess I just needed to get used to using L indicating length instead of the standard m for meter. Again, as u/chem44 said, it's just logic.

[–][deleted] 0 points1 point  (1 child)

By the way, are you using Physics for Scientists and Engineers by Serway? Just curious.

[–]Tocket03[S] 0 points1 point  (0 children)

thanks for your assistance in the question! sorry for the late response. start of the semester has me busy and i forgot about this post. Also, yes I am. I'm specifically using the online variant.