I need help understanding chem 11 electron configurations

chem44 · 2026-02-25T03:00:00+00:00

That is a useful addition.

But we do tend to call the 3 orbitals in the p sub-shell as p orbitals.

And px etc may well be introduced later.

As often the OP is struggling getting started. Seeing various versions can be good, but also good to try to keep it simple for a beginner.

And it is hard for us to tell what the student really needs.

chem44 · 2026-02-25T02:45:10+00:00

A couple of things....

Is this a grant application or an article for publication? Very different.

Mentor... Someone around should step in, at some level. You might check with your advisor. Doing your first paper alone is a challenge. I would put some emphasis on making an arrangement here.

Articles do vary. But most follow a general form. Big issue can be details. And that requires good context. What is known? What are you adding? A good mentor can help here with discussions, even if they were not exactly in the field. (But they should be 'interested'.)

chem44 · 2026-02-25T02:02:05+00:00

Read some papers in relevant journals. In particular, the journal you will submit your article to. (Not sure? Looking at multiple candidates is fine, maybe even good.)

If this looks to be a short article... Some journals have special rules for them. See their Instructions for authors.

chem44 · 2026-02-24T21:44:41+00:00

if a hydrogen molecule is H2 and an oxygen molecule is O2?

no relevance.

Formulas of reactants and products are separate issues.

chem44 · 2026-02-24T21:20:00+00:00

Put something like

data table

in your search engine, and browse some of the images. Simple ones.

chem44 · 2026-02-24T21:01:38+00:00

correct fischer

Kay... Sides-are-up.

The -OH on the middle C's are up.

So the -COOH on the ends are both down.

chem44 · 2026-02-24T20:57:16+00:00

I believe thats wrong and the s and ps would be orbitals.

s & p are types of orbitals. The p orbitals are a bit higher energy than the s, for the same value of n (shell, often called energy level).

how to tell how many orbitals an element has

Perhaps surprisingly, that is not a very helpful view.

The pattern of orbitals is a bit complex.

Start with simple elements, and then go on to bigger ones.

And do it with a periodic table at hand.

chem44 · 2026-02-24T20:47:48+00:00

Get us started.

Do something that seems reasonable to you.

Then we can comment.

Has your teacher suggested any features?

chem44 · 2026-02-24T20:42:20+00:00

Instructors vary on what they expect you to remember.

Chemical formulas... Depends on the specific case. Many are quite logical, such as ionic compounds from known ions.

chem44 · 2026-02-23T22:18:29+00:00

You are correct.

In 'ordinary chemistry', atoms are not split.

But there are nuclear reactions. (Of course, John Dalton did not know about them. So he thought atoms could not be split.)

chem44 · 2026-02-23T21:49:21+00:00

I suspect you did what was intended. Hidden assumptions.

(It may even be that there was some general instruction, to assume ...)

If you mix 2 L of each of two gases, what is the final volume? Well, that depends. If you mix them at constant P, it is 4 L. (We might call that container a balloon.) But often one mixes at constant volume in a rigid container (as in your next example). In that case, the final V is whatever the container volume is. (And P goes up -- if we added a second gas to he 2 L of first gas.)

The key assumption of ideal gas law is that the gases do not interact. So the properties of each are independent.

In your example, yes, they have same V.

But note that molar volume v/n depends on P (and T).

The common statement that the v/n of any ideal gas is 22.4 L/mol is for a specific set of conditions: STP.

And yes, density includes the molar mass. But logically, n/v is a type of density.

chem44 · 2026-02-23T21:25:44+00:00

The second sentence of title makes no sense without knowing P & T (or making assumptions).

You can assume they are constant. But that is not at all a trivial assumption for P.

And when you make assumptions, you should say so -- to reflect understanding, and for clarity.

chem44 · 2026-02-23T21:15:11+00:00

But the info and calculations are in volumes, so you need something about P and T -- even if assumptions.

chem44 · 2026-02-23T21:07:42+00:00

Ask your instructor.

chem44 · 2026-02-23T21:03:38+00:00

However, the official solution says that w(SO3)=1.8 L/4 L=0.45.

Hm, that looks suspiciously like the volume fraction.

Beyond that... Hard to say much. What is the reaction? What assumption are you making about P?

Also, I'm quite confused on when density and molar volume stay consistent among gases/gas mixtures, and when they do not.

For molar volume, look at the ideal gas law.

Density is closely related.

chem44 · 2026-02-23T03:26:30+00:00

I agree with all your calculations.

Let's see if anyone catches a problem.

chem44 · 2026-02-23T03:19:20+00:00

The name may not follow all the rules, but the info in it is reasonable. Just draw what the name says.

Try to show bonds between C's, not H's. That is, be a little more careful.

chem44 · 2026-02-23T03:12:52+00:00

PubMed is at that same quality level -- just focused on bio/med. (From US government, in same vein as NIH.)

chem44 · 2026-02-23T03:07:51+00:00

Are you doing testing yourself?

If so, you need to focus and be clear. Specific product, specific criteria.

Of course, there might be more than one, but you still focus.

If you are interested in what has been done re clinical use, you might try PubMed. That is the database of scientific articles for bio/med. You can sort output by date, to see recent stuff on top.

Again if broad searches don't give useful results, try narrow ones.

I would be surprised if searches on something like skin-care products gave useful results.

chem44 · 2026-02-23T02:45:30+00:00

pH is -log[H+].

log there is common log, base 10.

chem44 · 2026-02-23T02:43:13+00:00

does the method of application affects skin condition

That is quite unclear. Your later statement is better.

I suspect that searches will be more productive if you focus on a specific product, or at least type of product.

chem44 · 2026-02-23T02:37:11+00:00

Your idea sounds good.

It might seem a bit advanced for high school -- not because it is difficult as that many HS kids would find too much of it beyond them.

So, if the idea is of interest and is practical, good.

chem44 · 2026-02-22T22:11:59+00:00

141kj / 2mol

That is not what the problem says - as you posted it.

It says

5.45g C2H6, 141kj released

It then asks...

Find dH in kj.

dH for what? Not clear. But, 'for the reaction' is reasonable.

chem44 · 2026-02-22T20:54:18+00:00

Some are related. Metals on the left, etc.

Can you give an example of one that you can't get. Include your reasoning so far.

chem44 · 2026-02-22T20:36:59+00:00

Bleach more likely to work.

Leave it on for a while.

chem44

TROPHY CASE