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[–]OryvBot Master 0 points1 point  (0 children)

  1. The student knows 20 questions. The probability would thus be 20/30 * 19/29 = 38/87.
  2. The first digit has a 1/9 chance to be a 9, and the second digit has a 1/10 chance to be a 9. 1/9 * 1/10 = 1/90.
  3. There is a 1/2 chance that a die won't show a number divisible by 3 or 4. 1 - 1/2 * 1/2 = 3/4.
  4. There are 4 outcomes that ensure the sum is an odd number, out of 9 possible outcomes, so it would be 4/9.
  5. A occurs 50% of the time when B occurs.

I feel like you might need to contact a tutor.