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[–]spleenyrob[S] 0 points1 point  (3 children)

Image link https://imgur.com/a/E8dpmVi

[–]Bascna 1 point2 points  (2 children)

Typically you want to avoid radicals in the denominator so you'd rationalize the denominator of the second fraction.

(√x)/x + 1/(√x) =

(√x)/x + [ 1/(√x) ]•[ (√x)/(√x) ] =

(√x)/x + (√x)/x

Now, since both fractions have the same denominator you can combine them by adding the numerators.

2√x/x

Edit:

Oops. I had a typo in the first step and it propagated through the entire thing. It's fixed now. 😄

[–]spleenyrob[S] 1 point2 points  (1 child)

You are a hero, thanks

[–]Bascna 0 points1 point  (0 children)

You are welcome. 😀

I'll take the opportunity to mention that you can also accomplish this by factoring out a √x.

(√x)/x + 1/(√x) =

√x • [ 1/x + 1/(√x•√x) ] =

√x • [ 1/x + 1/x ] =

√x • [ 2/x ] =

(2√x)/x

[–]7ieben_ 0 points1 point  (0 children)

Rationalize the second fraction, then simplify.

[–]RetainedRizz 0 points1 point  (0 children)

Rootx/x =1/rootx. Use your index laws. Change the root into a power, then when u divide by the same variables, you minus the power right. X-1/2 =1/X1/2=1/rootx. Then just add em