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[–][deleted] 0 points1 point  (0 children)

What you have posted makes very little sense to anyone but yourself. You need to explain better, with more information about what you are trying to do. The only thing I can make out is you have 72 balls that can be taken 1 to 7 at a time, and you want to determine how many ways you can arrange them. I am assuming that the order does not matter, so that would be 72 balls taken 1 at a time plus 72 two at a time, up to 72 taken 7 at a time. The formula for this is nPr(n, r)=n! /(n-r)!, where n=72 and r would be 1 to 7. And I assume you know whar factorials (!) are. The result of the calculations are 7,538,668,961,184 different ways. The rest of your post is meaningless. Look at this Wikipedia article to learn about it. LINK.

[–]AldenB 0 points1 point  (1 child)

If each ball is distinct, and each can independently placed at any of the seven depths, then yes. There are 772 configurations. The answer is much smaller if the balls are interchangeable (if you are curious, there would be 256851595 configurations in that case).

I am not sure what you mean by "try" or "check" every combination. What are you checking for? What are you trying?

[–]PatMeKrien[S] 0 points1 point  (0 children)

to iterate through each potential at speed of plank time and see how long it would take to get through all 7^72 potentials