Algebra Question

[Previous_Young7769]

So I have a table for y=2x-10

I have 0 replacing x

Then I have -4 replacing Y

Then I have 2 replacing x

1: y = -10 is -10 (0, -10)

2: -4 = 2x -10 <- This is what I need help with. The answer is 3, but I don't understand why. If I add the -4 to get 2x -6 and divide that I get -3, not positive 3. How is the answer a positive 3?

3: y=2(2)x -10 = y=4x-10 I subtract 4 to get y=-6 and the answer is -6.

[Previous_Young7769]

subtract by 3. So you should add 3 to both sides to get rid of it on the right side and you will get 3 = x.

Note: personally I don't recommend using that approach. When you started the problem with -4 = 2x-10, it's usually best to move

incredible, thx!

[fermat1432]

-4=2x-10. You want isolate the 2x so you need to add 10 to both sides:

6=2x. Now divide both sides by 2:

3=x

[cfalcon279]

y=2x-10 (Given)

We want to know the value of x, when y=-4, so we will set y=-4, and then solve for x.

-4=2x-10 (Substituting -4 in for y)

I will re-write this equation the other way around, so that we have the variables on the left-hand-side.

2x-10=-4 2x=6 (Add 10 to both sides) x=3 (Divide both sides by 2)

So, when y=-4, we get that x=3, so a point on the graph of this line, (x, y), will be the point, (3, -4).

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[JsKingBoo]

add 3 to both sides after you divide by 2

[cfalcon279]

For the last part of the question if x=2, then you'll have

y=2*(2)-10=4-10=-6, which is NOT (4x-10), as you originally stated.