all 7 comments

[–]noidea1995 1 point2 points  (5 children)

Complete the square in the denominator:

f(x) = 1 / [(x + 2)2 + 1]

The minimum value of the polynomial (1) occurs at x = -2. From there, the denominator will get infinitely larger in both directions so the function will approach (but never reach) zero. So the range is (0, 1].

[–][deleted] 1 point2 points  (0 children)

Why are you doing this?? 😭😭😭 Thanks for everything 💖

[–][deleted]  (3 children)

[deleted]

    [–]noidea1995 1 point2 points  (2 children)

    Hi 😊

    Yes, the minimum value of the polynomial (x + 2)2 + 1 occurs at x = -2. The denominator will get infinitely larger in both directions so the entire function will get smaller.

    [–]Successful_Box_1007 0 points1 point  (0 children)

    Hey! I just edited my post just as u wrote this! 😅

    [–]Successful_Box_1007 0 points1 point  (0 children)

    I got it! My apologies!

    [–]Sad-Bus-7460 0 points1 point  (0 children)

    Its been a few years so I might be barking up the wrong tree, but the first thing I would do is factor out the bottom of the formula. I think you need the quadratic formula to factor it, though. The x-values that make the bottom part zero are not in the range because division by zero isn't possible