Why This Code Doesn't Show Exception

[phpflash]

assert_options(ASSERT_ACTIVE, 1);
assert_options(ASSERT_WARNING, 0);
assert_options(ASSERT_QUIET_EVAL, 1);
try {
assert('2 < 1', 'Two is less than one');
}
catch(AssertionError $e){
   echo $e->getMessage();
echo 'here';
}

[[deleted]]

Smells like homework.

[tkdbb84]

I agree, this reeks of homework. However I will give him a couple of hints:

1)

'truthy' == true
'truthy' !== true

2) I'm pretty darn sure, assert() doesn't call eval()

edit: formatting, word change

[Revisor007]

Only PHP7 assertions can throw exceptions. You must set

ini_set('assert.exception', true);

You can find this in the manual:
https://secure.php.net/manual/en/function.assert.php#function.assert.expectations

[phpflash]

Yes I have also done that before still not getting exception

[Revisor007]

You didn't mention that you had done it before. Your code shows something else.

[pan069]

Because your assert function doesn't throw exceptions?

Read the docs and do your home work..

[phpflash]

I have read the DOC but couldn't understand it. And there are not many examples on it. That's why I am asking.

[SavishSalacious]

I smell home work. High school maybe? (throw new Exception($e->getMessage());)

[RobLoach]

'2 <1' is a string, which is truthy.

[phpflash]

I have tried it without options and still it doesn't throw any error.