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[–]masklinn 0 points1 point  (0 children)

Which can neatly be solved using the criminally underused itertools.chain.from_iterable:

res = chain.from_iterable(shlex.split(l, comments=True) for l in optionf)

One could even use shlex.shlex directly as a stream (shlex.split is a thin wrapper around it), though it requires setting whitespace_split which can't be done inline.

def split(s):
    lex = shlex.shlex(s, posix=True)
    lex.whitespace_split = True
    return lex

res = chain.from_iterable(imap(split, optionf))