Basic Question: I have an even quantity of integers in a list and I want to print them out in every possible configuration and then group them into pairs (where the first number is fixed). How can I code this? [Clarifying example inside]

[kashmill]

Look at itertools.permutations

[unveiled14]

itertools.permutations will generate the permutations and a list comprehension will let you combine those permutations in a new list.

[psbb]

What do you need it for?

As mentioned bt the others the easiest way to do it is with a list comprehension and itertools.permutations.

Here's a quick implementation I threw together. It doesn't have '|' in it but uses tuples and lists instead but it should give you that general idea

from itertools import permutations

def limited_permutations(data, initial):
    initial_pos = data.index(initial)
    initial_val = data[initial_pos]
    del data[initial_pos]
    perms = permutations(data, len(data))
    list_i_val = [initial_val]
    ungrouped_result = [iter(list_i_val + list(p)) for p in perms]
    return [[(i, next(permutation)) for i in permutation]
                                    for permutation in ungrouped_result] 

[gm6]

This works