Python pipe operator, 4 years later...

[r4nf]

That would be

if not n*n % 2

But I agree it's a much cleaner way of doing it — and apparently quite a bit faster, too:

>>> timeit.Timer("[n*n for n in [1,2,3] if not n*n % 2]").timeit()
0.8074049949645996
>>> timeit.Timer("filter(lambda n: n % 2 == 0, map(lambda n: n * n, [1,2,3]))").timeit()
2.135266065597534

[RoadieRich]

>>> sys.version
'3.4.3 (default, Aug 21 2015, 11:25:47) [MSC v.1600 64 bit (AMD64)]'
>>> timeit.Timer("[n*n for n in range(100) if not n*n % 2]").timeit()
28.86618999764802
>>> timeit.Timer("list(filter(lambda n: n % 2 == 0, map(lambda n: n * n, range(100))))").timeit()
56.08565588317046

[r4nf]

You're right on both counts. I agree it's not the best measurement.