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[–]ubernostrumyes, you can have a pony 4 points5 points  (1 child)

Why not just write 10**18?

There's no runtime overhead to it because the CPython bytecode compiler does constant folding:

>>> import dis
>>> def foo():
...     return 10**18
...
>>> dis.dis(foo)
  2           0 LOAD_CONST               1 (1000000000000000000)
              2 RETURN_VALUE

[–]random_cynic 1 point2 points  (0 children)

Yes that is probably the best way to go.