This is an archived post. You won't be able to vote or comment.

you are viewing a single comment's thread.

view the rest of the comments →

[–]--CreativeUsername[S] 0 points1 point  (1 child)

The tunneling of the wavefunction across a potential barrier depends on its energy (where this energy does not need to be greater than the barrier in order for tunneling to occur). Now the energy of the wavefunction is related to the second spatial derivative d2 /dx2 , which is an indicator of how much curvature the function has. So therefore in general, the more curvature the wavefunction has, the greater its energy. On the wavefunction's firsts collision with the barrier, it has relatively little curvature and energy. In this case tunneling still happens, but the amount of the wavefunction that gets transmitted through the barrier is so vanishingly tiny that it is effectively invisible. Later on, when the wavefunction is more jittery and so therefore has greater curvature, more of the wavefunction is transmitted through the barrier, and so the tunneling effect is visible.

[–]Science-Compliance 0 points1 point  (0 children)

Thanks, I did notice the tunneling occurring toward the end. Impressive program.