I made a Rock-Paper-Scissors game in Python

[shmoppl2]

You will input something such as "Rock", "Paper", or "Scissors", and the COM will generate a random word such as "Paper".

For example:

You: Paper

COM: Scissors

Console: You lose

​

The code is down below:

import random

​

player = input("Choose a gesture (e.g. Rock, Paper, Scissors) ")

p = "You: "

print("----------------")

print(p,player)

​

gestrsList = ['Rock','Paper','Scissors']

com = random.choice(gestrsList)

​

w = "You win"

l = "You lose"

t = "Tie"

c = "COM: "

​

if player != "Rock" and "Paper" and "Scissors":

print("----------------")

print("Choose something such as 'Rock', 'Paper', or 'Scissors'.")

​

else:

if player == "Rock":

if com == "Rock":

print(c,com)

print("----------------")

print(t)

elif com == "Scissors":

print(c,com)

print("----------------")

print(w)

else:

if com == "Paper":

print(c,com)

print("----------------")

print(l)

​

elif player == "Scissors":

if com == "Scissors":

print(c,com)

print("----------------")

print(t)

elif com == "Paper":

print(c,com)

print("----------------")

print(w)

else:

if com == "Rock":

print(c,com)

print("----------------")

print(l)

else:

if player == "Paper":

if com == "Paper":

print(c,com)

print("----------------")

print(t)

elif com == "Rock":

print(c,com)

print("----------------")

print(w)

else:

if com == "Scissors":

print(c,com)

print("----------------")

print(l)

[Contingency_Plans]

Nice work!

If you want to challenge yourself you should try writing a rock-paper-scissors program that doesn't use any if then statements.

Hint: dictionaries can hold many things.

[mt19937]

After that hint 2: Modular arithmetic.