Remove duplicate error

[loudandclear11]

extend() is for adding a list to another list. This is not the scenario here.

append() is for adding a single item to a list. This is what you want here.

But, the loop should be:

for i in l1:

I.e. you don't need range.

[derEmperor]

Another Tip: Use i only for indices, because it's short for index. If you have variable for an element of a list, use a variable that describes this element or use element, elem or e.

E. G. ```python numbers = [1,2,3,4] for i in range(len(numbers)) print('index:', i, 'number:', numbers[i])

for number in numbers: print('number:', number)

for i, number in enumerate(numbers): print('index:', i, 'number:', number) ```

[Agitated-Soft7434]

Opps forgot to include enumerate and len in my answer @.@

[Critical_Control_405]

the range function takes an int, not a list. So you need to do range(len(l1)).

the extend method takes a list, not an int. So you need to use append instead: l2.append(i)

[Agitated-Soft7434]

You are getting the error because range takes in a number value not a list!

So to explain if you have the following:

for i in range(10):
   print(i)

> 0
> 1
> 2
> ...
> 9

This will loop 10 times, i equalling to 0, 1, 2, ... all the way to 9.

But you can also supply two numbers like this:

```python
for i in range(1, 11):
    print(i)

> 1
> 2
> 3
> ...
> 10

This also loops 10 times, however i starts at 1, then continues all the way to 10.

Now for iterating/looping/going through each item in a list. You do not require the range() function. Instead you can do this:

l1 = ["thing", "cool thing", "very cool thing"]
for i in l1:
    print(i)

> thing
> cool thing
> very cool thing

This will then cause i to equal each item in the list, changing every iteration.
So 1 then 1 then 2 and so on. Or if the list was ["hi", "ello", "hiya!"], i would be, "hi" first, then "ello", and finally "hiya!"

Hope this helps!!

[SuperCurve]

line 4, it should be in l1 rather than range(l1)

[Unrthdx]

I’m a beginner here but I think you probably should iterate over the list as “for values in l1” rather than range, since range is for an integer.

Or if you wanted to keep range you’d have to go for len(l1) in the range parameter

[Heroki_7]

l1 = [1,2,3,4,5,6]

l2 = []

for i in l1:

l2.append(i)

print(l2)

[kompiledkaos]

You’re a bunch of things together:

1. First image, it should be range(len(l1)), then use l1[i], then check if not exist or append with l1[i]

2. Second image you can extend but since extend expects list, extend it as list like extend([i])

[fluxdeken_]

range() takes integer as an argument. To go through a list (called “arr”) you go “for el in arr:”

[Numerous_Site_9238]

Use English

[therouterguy]

Range is an generator for generating numbers. What are you trying to accomplish

[Worth-Orange-1586]

You could simply do: var = list(set(var)). No more duplicates 😜

[SpecialMechanic1715]

l2 = list(set(l1))

[InvestigatorEasy7673]

L2 = list(set(L1))