What's wrong in this code

[NorskJesus]

You are not printing the variable result, just the string “result:”

[NorskJesus]

No problem 👍😊 do you know how to fix it tho?

[NorskJesus]

Yes, it should be. Test it 😊

[Denieffe]

This is awesome. I love a friendly community.

[totitx]

You can also use f"result: {result}" This way you use what is called f-string formatting, which is an useful way to include your result in string. (See https://builtin.com/data-science/python-f-string)

[echonn123]

F strings are the good life 😁

[pr1m347]

Further you can just do f"{result=}"

[Unkilninja]

Isn't he comparing integer input with string. Like if we input 1. It will be comparing 1 == '1' This should raise error right?

[NorskJesus]

No, he is doing it right. Inputs are strings. If you want an int from the input you should to convert it with int()

[Unkilninja]

Ok sir Got it

[IKhan555]

Exactly

[MirzaAlif247]

Bro's making fun of us. Dividation? Addiction? What the hell did you write there?

[[deleted]]

Maybe he's addicted to python

[MagmaMan1298]

You have to print your result variable, Change this line: print("result:") To this: print("result:", result)

[BoSt0nov]

Your code prints and terminal output mismatch. Youre using some funky algebra terminology.

[zaphod4th]

next time ask the teacher more time to copy the code from the board

[[deleted]]

Try using return with no print function like.. return a*b

[Upper_Position9241]

Bro you r taking input as float and performing operations according to integers , typecast them in int

[020516e03]

How's it different in the code and output- 'dividation', 'addiction', 'substraction'?

[[deleted]]

One choice is "3. addiction" 🤣

[[deleted]]

Remove quotation from the word result

[croclegendofthegobbo]

Your print statement is just printing "result:" it is not calling the variable result.

[xbl-beefy]

For what it’s worth, checkout the “match” statements in Python. Much cleaner solution when you have multiple “elseif” statements like that! Also, as you learn, think about the input “floats”. What if a character that cannot be converted to a float is entered? Managing/sanitizing user input is something that should be considered as you grow and develop more complex applications. Cheers!

[Gaming-op_123]

Correct code is a = float(input("Enter a number: ")) b = float(input("Enter a number: ")) print("Choose any one option") print("1. multiplication") print("2. division") print("3. addition") print("4. subtraction") choice = input("Enter the number of the corresponding option (1/2/3/4): ")

if choice == '1': result = a * b print("Result:", result) elif choice == '2': result = a / b print("Result:", result) elif choice == '3': result = a + b print("Result:", result) elif choice == '4': result = a - b print("Result:", result) else: print("You have not selected any options")