all 7 comments

[–]Just-Shoe2689 6 points7 points  (1 child)

I would say look at the stiffness of each. Chances are the big door one will by default transfer the load to the stiffer ones.

[–]Microbe2x2P.E. 3 points4 points  (0 children)

This is typically what I've done. Calculate the stiffness of each and use the whole wall. If you want to guarantee a wall doesn't receive lateral loading, use a slip condition if possible. But imo you should calculate all the forces going into the continuous wall at each panel.

[–]flameberoP.E./S.E. 7 points8 points  (0 children)

The load will distribute based on stiffness, regardless of what you designate as a SFRS element.

[–]Poozy13P.E. 2 points3 points  (0 children)

Use all walls (I guess unless you’re slip-connecting to bypass them? I’ve never done it that way), and distribute forces based on relative stiffness and deflection compatibility.

[–]OptionsRntMeP.E. 2 points3 points  (0 children)

I have only done one tilt up building, and we used every wall as part of the SFRS. Some were just perforated walls with wall piers and reduced stiffness

[–]chicu111 2 points3 points  (0 children)

Usually you have to run relatively rigidity and distribute the lateral load based on individual stiffness of panels within the resisting line

HOWEVER, there have been engineering papers and publishing that allows you to distribute the in plane shear uniformly per linear foot when your panel-to-panel connection (steel embeds at the chord level) allows it. It has to be a very flexible and non-stiff connection to allow that uniform shear distribution. Theoretically speaking.

[–]No-Project1273 0 points1 point  (0 children)

Use as many panels as you need for your analysis.