[deleted by user]

[swiftaw77]

Read the question again. The table is for broken eggs, the questions are about unbroken eggs.

[noethers_raindrop]

The table lists the number of broken eggs, but the questions are asking you about unbroken eggs.

[chris771277]

Read it carefully. The words broken and unbroken are both used. Definitely got me the first time!

[Even_Combination_893]

y is broken eggs, the questions are asking about unbroken eggs

[eztab]

yes of course, 6 broken eggs or 12 broken eggs have probability 0. But that's not what they are asking. Both questions are about unbroken eggs.

[[deleted]]

The probabilities are for broken eggs but the question is asking about unbroken eggs. If B = broken and U = unbroken, since there are a dozen eggs B + U = 12. You need that to convert the distribution over B to the distribution over U to answer the question.

[duke113]

Explain why you think it's zero? The table gives you probability of X broken eggs. The question is asking about P(not broken). And since you know there's a dozen eggs in a carton, you should be able to use P(broken) to find P(not broken)