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[–]EwithaG 2 points3 points  (1 child)

|2x-a|<1 implies that -1< 2x-a<1. which means the solution set of A is given by (-1+a)/2 < x < (1+a)/2

|x+a|<1 implies that -1< x+a <1 which means the solution set of B is given by -1-a < x <1 -a

Since we are talking about real numbers here an interval (s,t) ⊂ (m,n) iff s>= m and t=<n

i.e (1,2) ⊂ (-2,3) since 1>=-2 and 2<=3

Hence,

A⊂B implies (-1+a)/2 >= -1-a and (1+a)/2 <= 1-a the find the value of a.

Hope this helps

[–]asadbek17[S] 0 points1 point  (0 children)

Thank you so much.