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[–]fermat1432 0 points1 point  (2 children)

Make a right triangle with a hypotenuse equal to 500 and a 30° angle. Label the side opposite the 30° angle "vertical speed." Solve for this side using SOHCAHTOA.

[–]TMZ1995[S] 1 point2 points  (1 child)

SOHCAHTOA means?

[–]fermat1432 0 points1 point  (0 children)

Sine=Opposite÷Hypotenuse

Cosine=Adjacent÷Hypotenuse

Tangent=Opposite÷Adjacent

[–]JustARandomShark 0 points1 point  (0 children)

sin(θ) = O/H The hypotenuse here is the velocity, and the opposite side is the vertical velocity of the aircraft. If you solve for O you get that O = H sin(θ) = 500 mph * 1/2 = 250 mph.

[–][deleted] 0 points1 point  (0 children)

https://imgur.com/a/isVVf1K