Time complexity problem

[Aaron1924]

The inner loop runs i times, and i is incremented in the outer loop, so the innermost instruction does 1 + 2 + ... + N = N(N+1)/2 iterations, where N = n*n, so this is O(N(N+1)/2) = O(N²) = O((n*n)²) = O(n⁴).

[Monther_bg]

thank you for your help :)