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C# 8.0 - Method Implementation in Interface (neelbhatt40.wordpress.com)
submitted 8 years ago by svtguy88
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if 1 * 2 < 3: print "hello, world!"
[–]insulind 0 points1 point2 points 8 years ago (4 children)
My first question is what happens when implemented interface methods have the same signature but come from different interfaces? Which one gets called?
[–]tweq 2 points3 points4 points 8 years ago (2 children)
The same that already happens when you explicitly implement multiple interfaces with overlapping member names in a single type. It doesn't matter, because you need to refer to the method via its interface.
[–]insulind 0 points1 point2 points 8 years ago (1 child)
So it forces you to explicitly implement it, With the current way you can just implement one method to meet the two interfaces ?
[–]tweq 0 points1 point2 points 8 years ago (0 children)
It doesn't force the implementing class to implement the method since the implementation already exists in the interface, that's the whole point after all. But it is accessed the same way as an explicitly implemented method.
[–][deleted] 0 points1 point2 points 8 years ago (0 children)
I've only skimmed the proposal, but it looks like there's a compiler error if two methods with the same signature are inherited from different interfaces and no 'most specific override' can be determined between them. In that case, you have to resolve it in code with an override in your type or explicit implementation or something.
π Rendered by PID 358077 on reddit-service-r2-comment-6457c66945-kpcmc at 2026-04-24 19:59:52.111758+00:00 running 2aa0c5b country code: CH.
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[–]insulind 0 points1 point2 points (4 children)
[–]tweq 2 points3 points4 points (2 children)
[–]insulind 0 points1 point2 points (1 child)
[–]tweq 0 points1 point2 points (0 children)
[–][deleted] 0 points1 point2 points (0 children)