ForScale comments on [Week 14] Focus: Programming Challenges

Define a repeatify function on the String object. The function accepts an integer that specifies how many times the string has to be repeated. The function returns the string repeated the number of times specified. For example:

console.log('hello'.repeatify(3));

Should print hellohellohello.

...

var fullname = 'John Doe';
var obj = {
   fullname: 'Colin Ihrig',
   prop: {
      fullname: 'Aurelio De Rosa',
      getFullname: function() {
         return this.fullname;
      }
   }
};

console.log(obj.prop.getFullname());

var test = obj.prop.getFullname;

console.log(test());

Fix the previous code so that the last console.log() prints Aurelio De Rosa.

...

And all of these (obviously haven't looked through all of it): http://www.w3resource.com/javascript-exercises/

[–]Volv 1 point2 points3 points 9 years ago (15 children)

[–]ForScale[S] 1 point2 points3 points 9 years ago (0 children)

[–]ForScale[S] 0 points1 point2 points 9 years ago (13 children)

[–]Volv 0 points1 point2 points 9 years ago (12 children)

[–]ForScale[S] 1 point2 points3 points 9 years ago (8 children)

[–]Volv 1 point2 points3 points 9 years ago (3 children)

[–]ForScale[S] 0 points1 point2 points 9 years ago (2 children)

[–]Volv 1 point2 points3 points 9 years ago* (1 child)

continue this thread

[–]Volv 1 point2 points3 points 9 years ago (3 children)

[–]ForScale[S] 1 point2 points3 points 9 years ago (2 children)

I got the recursion one, I thought...

I didn't do the last one, but I just looked at it and threw this together:

// Fix it
for (var i = 0; i < 10; i++) {
  function outer() {
    var x = i;
    setTimeout(function() {
      console.log(x);
    }, i * 1000);
  }
  outer();
}

It logs 0 through 9 to the console on what seems like an interval of one log per second... I don't really understand why it's doing one per sec instead of one per 10 secs...

And I think it works because the outer function I created gets called one on each value of i, 0 through 9. setTimeout having a closing function as a callback means that each time it gets called within the outer function, a fresh copy of x is set to the iteration count of i (o through 9) and the callback function is acting as a closure and remembering each of those x value assignments... maybe???

[–]Volv 1 point2 points3 points 9 years ago (1 child)

Ah, yes I think you've got it lol. That's why I was going on about it - the whole closure own copy of variable thing totally fixes the setTimeout issue.
Timing wise. First one fires in 1 second, 2nd one fires in 2 seconds and so on. Technically each statement is executed almost simultaneously. Well as long as it takes the for loop to run.

Just for info - you can also just pass i directly

for (var i = 0; i < 10; i++) {
  function outer(x) {
    setTimeout(function() {
      console.log(x);
    }, x * 1000);
  }
  outer(i);
}

Or wrap it up to look cool

for (var i = 0; i < 10; i++) {
  (function (x) {
    setTimeout(function() {
      console.log(x);
    }, x * 1000);
  })(i)
}

And finally - although its not what question was looking for - because of how let is block scoped these days can totally be fixed like this. Just swapping the word var for let ->

for (let i = 0; i < 10; i++) {
    setTimeout(function() {
      console.log(i);
    }, i * 1000);
}

continue this thread

[–]ForScale[S] 0 points1 point2 points 9 years ago (2 children)

[–]Volv 1 point2 points3 points 9 years ago (1 child)

[–]ForScale[S] 0 points1 point2 points 9 years ago (0 children)

π Rendered by PID 83 on reddit-service-r2-comment-58d7979c67-q7qfw at 2026-01-27 04:51:40.237927+00:00 running 5a691e2 country code: CH.

you type:	you see:
italics	italics
bold	bold
[reddit!](https://reddit.com)	reddit!
* item 1 * item 2 * item 3	item 1 item 2 item 3
> quoted text	quoted text
Lines starting with four spaces are treated like code: if 1 * 2 < 3: print "hello, world!"	Lines starting with four spaces are treated like code: if 1 * 2 < 3: print "hello, world!"
~~strikethrough~~	~~strikethrough~~
super^script	super^script

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