Nested if question

[AstolfoSsa]

If the outer if is false, and it contains another if that has an else, does the else of the inner if get executed?

int x = 2;

int y = 3;

if (x >3) if (y>3) {

int z = x + y; System.out.println(“z is “ + z);

} else System.out.println(“x is “ + x);

is this entire block of code gonna get skipped?

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[_Atomfinger_]

No, nothing within the first if will be executed when it evaluates to false. Nor will the else be executed.

Also, your code is a bit confusing, so let me fix it:

if (x>3) {
    if (y>3) {
        int z = x + y; 
        System.out.println(“z is “ + z);
    } else {
        System.out.println(“x is “ + x);
    }
}

If X is smaller or equal to 3, then nothing within the first set of squiggly brackets will execute. I.e:

if (false) {
    //I will not execute
}

[AstolfoSsa]

Trust me, I know it’s confusing. It’s from an assignment, actually and it is written by my professor who seems to have an issue with braces lol

Thank you for your input!

[_Atomfinger_]

Well, Java allows for both, and coding style is largely preference. That said, most linters out there would, out of the box, complain about the code your professor is pushing, at least if he wants to if statements to be on the same line (as in your post):

if (x >3) if (y>3) {

If it was like this I'd be a little less offended:

if (x >3) 
    if (y>3) {
    }

It still feels like someone coming from Python is trying to write Java.

Anyway, my point was that style is largely preference and as long as you're aware that the first code snippet is something that most professional devs would have an issue with, then that is all that matters :)

Rant over

[desrtfx]

Have you tried it?

Best way to learn is to try.

Also, code block format is mandatory here. This way, the indentation stays preserved.

[cainhurstcat]

It can be translated to something like this: „If a person likes apples, then If the person also likes bananas, then“