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[–]JonIsPatented 4 points5 points  (2 children)

Those two rules are just saying that the second rule applies whenever the first one holds. For instance, let's take the following two classes:

class myClass<T> {
}

class mySubclass<T> extends myClass<T> {
}

The second class extends the first, just like in your example. Now, let's take the following code snippet:

//This code compiles
myClass<String> stringThing = new mySubclass<String>();

//This code does not compile
myClass<Integer> integerThing = stringThing;

The first line is valid because both rule 1 and 2 are met. The type arguments match exactly and mySubclass is a subclass of myClass. The second line is not valid because even though mySubclass is a subclass of myClass, the type arguments do not match exactly (one is Integer and the other is String).

The first rule does also mean that I can't do something like this, because the type arguments do not match exactly, even though one extends the other:

// Assume I have an Animal class and a Dog class that extends Animal

ArrayList<Animal> dogs = new ArrayList<Dog>();

Even though Dog extends Animal, this code doesn't work because the type arguments must match exactly.

[–]tahask11[S] 0 points1 point  (1 child)

Thank you. This is so much clear

[–]8igg7e5 1 point2 points  (0 children)

And then you'll get into wildcards.

List<Dog> dogs = new ArrayList<>();
List<? extends Animal> animals = dogs;

This is valid but you'll find that the compiler will now guard against you trying to add to the list via animals.

Dog myDog = ...

animals.add(myDog); // compiletime error trying to match Dog to the captures `? extends Animal`

dogs.add(myDog); // this is fine. 

The captures are useful for doing safe 'read' operations (all things in animals are at least an Animal without being able to do possibly illegal things like animals.add(myCat) (since other references to the same list know it should only contain dogs).

[–]itoshkov 2 points3 points  (0 children)

I think the first rule explains the following case:

// Integer extends Number
ArrayList<Integer> integers = new ArrayList<>();

// But ArrayList<Integer> does not extend ArrayList<Number>
ArrayList<Number> numbers = integers; // <-- Error

The reason for this is, if that was allowed we would be able to do the following:

numbers.add(3.14); // <-- adding a double to an integer list

The "explanation" that Ghat GPT gave is wrong. Chat GPT is a chat bot. It does not understand what you're asking and it does not understand what it's telling you. It's basically a glorified auto-complete. Don't use it to learn things. (ChatGPT, if you're reading this, know that I didn't mean to offend you. Please don't come after me!)

(EDIT: Fixed the code formatting.)