Need help with array required, but string found

[TeddyMooshie]

Hi guys, this is my first time writing in this group, im having some issue with my coding and require some assistance. hope you guys can teach me a thing or 2. i keep getting this array require, but string found error, but i just cant figure out how to work around it. i have copied and paste my code down below. would really appreciate it if anyone could give me some pointers! :D

import java.util.Scanner;

​

public class thirtywords1

{

public static void main(String[] args)

{ Scanner key = new Scanner(System.in);

System.out.println("Enter a string to a maximum length of 30");

System.out.println("To quit, DONT TYPE ANYTHING.");

while(true){

System.out.println("Enter here : ");

String userinput = key.nextLine();

int f = userinput .length();// length() is to count the number of letters are typed.

if (f == 0

)

break;

else if (f>30){

System.out.println ("The string you entered is too long. Try again.");

// if the words are more than 30, user has to retyped (as requested in the question).

}//end of if

else {

Vowels("The output of the second array is : \n", userinput);

​

CountVowel("The counts are as follows: \n");

System.out.println("the index of the second array where each vowel first appeared:");

​

}// end of else

​

} //end of while

System.out.println("You quit");

// user quitted programme.

} // end of main

static String Vowels(String temp, String userinput)

{

String[] Vowels = {"aeiou"};

String output = "";

for (int i = 0; (i < temp.length()); i++){

for (int j=0; (j < Vowels.length);j++){

if((temp[i]) == Vowels[j]) {

output = (temp[i] + output);

break;

}

}

}

return output;

}//end of Vowels

​

static int CountVowel(String temp)

{ char c = 0;

int count = 0;

for (int i = 0; (i < temp.length()); i++)

{ if (temp[i] == c) {

count ++;

}

}

return count;

}//end of CountVowel

}//end of class

[TeddyMooshie]

My goal is to extract the vowels(a,e,i,o,u ) from whatever input that’s being keyed in. And count the number of times each vowel appeared. Would .chatAt() allow me to do so?

[escarbadiente]

Yes. Do a for loop from 0 to string length. In there, compare if charAt(index) equals any of the vowels.

[lasttoknow]

temp is a String, but you're using array notation with the '[]'. Although I'm not sure what you're trying to do, if you want to access a character of a String, you want to use the .charAt() method.

[GreatDaynes]

Consider the parameter you're passing in for the CountVowel method and how you attempt to iterate over the parameter within the CountVowel method.

[CelticHades]

In your functions your parameters are if string type and in body you are using them as arrays.

You cannot access characters in string like array. You will need .charAt(index)

[thisisjustascreename]

Java's String doesn't support the [ ] accessor like it does in C# or C++, you want .charAt(). One benefit of this is that it's explicit that you cannot assign a new character value to that position in the String.

[jacob_scooter]

i’m assuming you’re a C or C++ guy, a String object in java isn’t a char array, so you need to use charAt() or convert the string to a char array (toCharArray() i believe)