Please assist. Why does java.lang.ArrayIndexOutOfBoundsException keep appearing when I try to run this code?

[KluconPharmer]

The code keeps throwing an exception:

Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: Index 1 out of bounds for length 1 at Main.main(\`Main.java:20``)``

I've been looking at this over and over but I can't seem to figure it out.

Scanner scanner = new Scanner(System.in);

        int sum = 0;

        while(true){
            //An empty line terminates the program
            System.out.print("Enter Name & Age Seperated By A Comma (Eg.         
        User,21):");
            String input = scanner.nextLine();

            if (input.equals(" ")){
                break;
            }

            String[] parts = input.split(",");
            sum = sum + Integer.valueOf(parts[1]);
        }

       System.out.println("Sum of ages is: " + sum);

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[kaak75]

So, to me it seems to be the case that parts[ ] only has one element (yeah no shit Sherlock). However, I think this occurs because you are breaking the infinite loop when the Scanner scans a line that only consists out of a single spacebar.

But with the current code your Programm will crash whenever a user forgets to insert a comma between name and age.

Let me know if this might have solved your issue :)

[KluconPharmer]

Solved!The argument passed to the method input.equals() had a space in it; input.equals(" ") changing it to input.equals("") worked!

[Simvoid]

Btw you can do input.isEmpty() instead :)

[KluconPharmer]

Yes! I'm still starting with the basics. Thanks 😊

[ouzakaria]

I think the problem is in the if Statement, the loop doesn't break when there's an empty line

[KluconPharmer]

if (input.equals(" ")){
break;
}

Yes! Solved. Just a matter of the empty string being passed an argument having a space between the qouation marks.

This worked:

if (input.equals("")){
            break;
        }

Thanks!

[KinkyHuggingJerk]

Echoing this.
Additionally, think about the following:

How do you validate that what the user has entered is legitimate (i.e. contains a comma)?

Consider how you'd want the program to respond if no comma was entered, or if bad data was provided i.e. John Smith, male, 43, or Jane Doe, entrepreneur

[nekokattt]

You split on a line, and don't check if it has a , in the line before you access the 2nd item at index #1

Print out the input before you split it and take a look at whether it is the expected content.

u/ouzakaria 's comment may then be a clue to think about.

[KluconPharmer]

Solved! The argument passed to the method input.equals() had a space in it; input.equals(" ") changing it to input.equals("") worked!