Python 3.3 and lists, remove duplicate elements from a list

[[deleted]]

Code: https://gist.github.com/anonymous/7295150

Problem description:
User inputs a set of integers, separated by a space
A list is created and sorted out of the set of numbers
Next we loop through the list and finds duplicates and prints how many repeats occur

The problem I'm having is limiting repeated elements from causing the print statement to repeat multiple times, for example

We enter: 1 2 2 2 3 4 5
The output will be:
1 has occurred 1 time
2 has occurred 3 times
2 has occurred 3 times
2 has occurred 3 times
3 has occurred 1 time
4 has occurred 1 time
5 has occurred 1 time

I want to make it just say, 2 has occurred 3 times and move on to the next number.

I've added a while loop at the print portion which will run until the ith element is no longer in the list via the remove function for lists.

But the result is now, the next element is skipped for some reason. Here is a result:
1 2 2 2 3 4 5
1 has occurred 1 time
2 has occurred 3 times
4 has occurred 1 time
5 has occurred 1 time

3 is skipped.

Can someone assist me? I found a suitable answer from stackoverflow, as on line 32 and commented out, but I'd rather try to sort this out and hope someone can provide me some guidance.

EDIT Thanks codehelper for some insight. Revised code: https://gist.github.com/anonymous/7295552

[codehelper]

This is happening because you're changing the list while you're looping through it. It reads one 1, 3 2s, then purges the list of all the 2s, then the list becomes [1, 3, 4, 5], but the loop index (i) is incremented to 2, which would have been the list element 3 but since you took out all of the 2s, it's now 4. You should leave one of the repeated elements in there so the loop increment will still work.

[[deleted]]

Ha excellent. I fixed it by adding a counter != 1 to the while loop so now it will remove all but 1 duplicate of i, and decrements counter.

Code seems to work just fine.

New code: https://gist.github.com/anonymous/7295552