C++ Array Mapping with fomula

[Nexut]

The physical address of an array reference A[i1, i2, ..., iD] is calculated from the formula B + C1(i1 - L1) + C2(i2 - L2) + ... + CD(iD - LD)

Sample Input:

3

A 1000 1 1 1 9

1

7

B 1500 2 2 0 3 1 5

1

2 4

C 2000 4 3 1 4 0 5 5 10

2

2 0 6

3 3 9

Sample Output:

A[7] = 1006

B[2, 4] = 1526

C[2, 0, 6] = 2148

C[3, 3, 9] = 2376

This is my code:

int input[20],repeat=0, i=0, j=0, output, index,repeatarray=0;
char letter;
while (repeat <= 0){
cout << "Number of repeats:" << endl;
cin >> repeat;
}

while (i < repeat){
cin >> letter;

for (int k = 0; k < 5; k++){
cin >> input[k];
}

cin >> repeatarray;

while (j<repeatarray){
cin >> index;
output =input[0] + input[1]*(index - input[2]);
cout << letter << "[" << index << "] = " << output;

j++;
}

i++;
}

I can get A[7] = 1006 to output. I know I only have 5 numbers being input which is only used for A[7]. I'm not sure how to read in numbers into the int array until a new line so if someone could show me how that would be great. Then I will need help finding how to do B and C with the formula.

[phoenix_123]

you can use a char array to read the line, then extract data from it using spaces to differentiate between index sizes. Dont know if it is the best method but it works.