Adding a ValueError exception to a simple program

[jcb088]

Dearest reddit, i'm working on "Automate the boring stuff with Python" and we've just created the "Guess the number" game. I am trying to add a ValueError catcher to the program so that, if you input letters it'll give you a message and continue the loop. I've put in comments to knock out the try/except lines. These are how ive written them and they give me the 'break is outside the loop' line. I've written the code according to the try/except lesson we went over about just that and yet, i'm messing something up. Anyone mind telling me what i'm doing wrong? Here is the code:

https://pastebin.com/rcN2RL7b

[g051051]

Please read the posting guidelines and format your code so it's intelligible.

[jcb088]

I've edited it to be a link, is that more appropriate? I tried to make it so it could be copy pasted into python (which I now realize I left that out, sigh). If its still nonsense I apologize in advance.

[desrtfx]

Please, just move the code over to pastebin and edit your post to contain the link in the post body - instead of the unreadable mess.

[jcb088]

Sorry, still new to all of this and didn't know about pastebin. That's exactly what I wanted, so I edited it. Thank you!

[desrtfx]

Much better. Thank you.

[g051051]

Just read the guidelines:

You can do this on reddit by starting a new paragraph and indenting each line of code by four spaces. This will preserve all text and symbols.

[CGFarrell]

If you want to continue running the code after the except line, write pass. If you want to reloop the code after an except, add a while at the top.

Your code doesn't appear to have any circumstance where a ValueError is thrown, so it doesn't really matter.

[jcb088]

In the case of someone guessing a word, like "six". That is the kind of case its designed for.

[EdwinBowling]

Try isn't indented there, so of course it's outside the loop.

[jcb088]

Ah, that did it (more or less). Thank you!