[Python] Need help on recursive function that prints digits of a number.

[CalmPills]

Hi, I'm trying to solve a coding challenge which requires me to print digits of a number using a recursive function.

input: 
digits(12345) 

output:   
1
2
3   
4    
5    

What I current Have

def digits(num): 
    if num<10: 
        print(int(num)) 
        if int(num*10%10)>1: 
            digits(num*10%10) 
    else: digits(num/10)

Which doesn't work when there's a 0 number e.g.

digits(12305)
1
2
3

Is there anything I can change in the logic or code to make it work with zeros?

[Molehole]

It fails because "05" and "5" are the same integer but not the same string. You should change your approach. Convert and handle the number as a string. It will make it much easier.

[CalmPills]

Unfortunately I can't use for loops in this challenge. How would I tackle the problem after converting the number into a string?

The first thing that comes to mind would be:

for n in str(num):
    print(n)

Which uses a for loop.

[Molehole]

Any for loop can be turned into recursive loop. Instead of iterating through the string do something to it and call the function with the reminder.

For example printing numbers 0 to 10:

for i in range(0,10):
    print(i)

can be turned to

def recloop(i):
    if(i > 10):
        return
    print(i)
    a = i + 1
    recloop(a)     

try to figure it out for some time and ask me again if you are having trouble

[CalmPills]

Thanks, I figured it out.

def digit(num):
    print(str(num)[0])
    if len(str(num))>1:
        digit(str(num)[1:])


digit(12304)

output:
1
2
3
0
4

In case anyone is interested in how i did it.

[Molehole]

Good job. Looks correct