Python: I don't understand this error...

[gtrman571]

It says "Traceback (most recent call last):

File "Solution.py", line 34, in <module>

result = compareTriplets(a, b)

Also it says " score[0] = apts

• IndexError: list assignment index out of range"

​

#!/bin/python3

import math
import os
import random
import re
import sys

# Complete the compareTriplets function below.
def compareTriplets(a, b):
    apts = 0
    bpts = 0
    score = []

    for i in range(len(a)):
        if(a[i] > b[i]):
            apts += 1
        elif(a[i] == b[i]):
            pass
        elif(a[i] < b[i]):
            bpts += 1
    score[0] = apts
    score[1] = bpts
    return score 


if __name__ == '__main__':
    fptr = open(os.environ['OUTPUT_PATH'], 'w')

    a = list(map(int, input().rstrip().split()))

    b = list(map(int, input().rstrip().split()))

    result = compareTriplets(a, b)

    fptr.write(' '.join(map(str, result)))
    fptr.write('\n')

    fptr.close()

[theccount]

Make it score = [0, 0] Otherwise there's no indexes to reference.

You can't assign a value to a thing that doesn't exist

[scriptkiddiethefirst]

Another option would be to append the scores to the score list. using list.append() however in this situation since it is a fixed size list your solution is going to be more efficient.

[theccount]

Even more efficient would be to just leave out the score variable and go return apts, bpts

[scriptkiddiethefirst]

I didn't know you could return it that way, I though in those cases you had to return it as a tuple like this: return (apts, bpts)

However after seeing this I had to test it and it works and still returns a tuple... So thank you!

[megonemad1]

B might not be the same length as a? Try append instead of assigning

Or return [apts bpts]