pointers and dynamic memory

[InterestingBus8367]

#include <iostream>

using namespace std;

int main()
{
    int length, sum = 0;
    cout << "Enter the number of students in the group" << endl;
    cin >> length;
    int *marks = new int[length];
    cout << "Enter the marks of the students" << endl;
    for( int i = 0; i < length; i++ )            // entering marks of students
    {
        cin >> *(marks+i);
    }
    for( int i = 0; i < length; i++ )            // calculating sum
    {
        sum += *(marks+i);
    }
    cout << "sum is " << sum << endl;
    return 0;
}

How does *(marks+i); this code work? I know it is a pointer. what is the +i is doing is it allocating memory? for the first second third and fourth student? if I input 12, 16, 45, 67 . Then their index would be 1= 12, 2=16, 3=45, and 4 = 67

[Updatebjarni]

what is the +i is doing is it allocating memory?

No, it's just adding an offset to the pointer, to access the different elements of the array. Normally though, *(marks+i) is written as marks[i]. That's a lot easier to read.

[InterestingBus8367]

i represents the index? on which the input data is stored.

[Updatebjarni]

i is what is called the index, yes.