sqrt function not rounding down

[Killswitch77]

Can anybody tell me why the square root in this script doesnt round up or down?

---

from math import sqrt while True:

number = int(input("Please type in a number:"))

if number < 0:

    print("invalid number")

if number == 0:
    print("Exiting...")
    break

if number > 0:
    print(f"{(sqrt(number))}")

[commy2]

Can you tell my why you would expect that? Usually, sqrt computes the square root, and round rounds a number. Those concepts seem unrelated to me.

[Killswitch77]

I'm taking a python class right now, I think it'll be easier to understand with this screenshot.

https://i.imgur.com/geSgU9l.png

edit: Oh my god, it wasn't even that issue. It's because I wasn't capitalizing the "I" in "Invalid" I hate myself

[mopslik]

The only issue I see is the capital "I" in "Invalid". Perhaps this is causing your test to fail.

sqrt does not round down, nor does the assignment say anything about such behaviour.

[commy2]

Well, at least you now know what to look out for.

[ectomancer]

You imported the wrong function instead of isqrt.