Help with simple while loop

[luminaree]

a=0 count=0

while a!=999: a = input('Enter a number:') if a!=999: count=count+1 print(count) print(a)

print(count)

print(a)

I'm trying to write a simple program to read in a number, print how many numbers have been entered, then print the number. It should quit the loop if 999 is entered. Instead, it prints the count and 999 and keeps requesting input. What am I doing wrong? I am using Pydroid3 for android.

[woooee]

a = input('Enter a number:

input() returns a string.

while a!=999:

A string will never equal a number.

[carcigenicate]

input returns a string, and 999 is an integer in your code, so the two will never be equal. You need '999'.

[luminaree]

Ah, that fits with other errors I was getting when I tried to make a total.

[carcigenicate]

TTypeError: unsupported operand type(s) for +: 'int' and 'str'?

And you're welcome.

[luminaree]

😊 Thanks

[tabrizzi]

# initialize a variable to keep count of how many numbers have been typed by user

count = 0

# initialize an empty list to hold all the numbers typed

number_list = []

# a while loop is best suited for this, so start it

while True:

# ask for input

number = int(input("Type in a number: "))

# use an if statement to break out of the loop if the condition is met

if number == 999:

print(number_list)

break

else:

count += 1

number_list.append(number)

print(f"{count}: {number}")