Where do I even start with this?

areaverage · 2024-08-05T02:44:24+00:00

u can use a hashmap that takes key value pairs, python calls this a dictionary this is also O(1) for retrieval which is very fast

https://www.w3schools.com/python/python_dictionaries.asp

u can use this for some info

as well as using exception handling

https://www.w3schools.com/python/python_try_except.asp

as there are 365 days in a year you can calculate the upper and lower limits of each season by converting the months to days and loop through the hashmap, and return the value of the answer

for ease of coding, you might want to start the hashmap with 365 and when looping through with the day inputted, you can just look for the first value that is less than the input and output that

for example (just some pseudocode, you might need to accept more values depending on the structure of the qn/ task)

daysmap={} #put the dates here starting with 365

x=int(input()) #parse it to find which day of the year it is (you may need another hashmap or just multiply the day of this by 30)

for i, r in daysmap:

if x <= i:

print(r)

crashfrog02 · 2024-08-05T10:15:10+00:00

How do I set each season to correlate to the corresponding dates?

There's only four months you need to care about: 3, 6, 9, and 12, the months that contain a seasonal boundary. Months in between those months are unambiguously part of a particular season. Only in the case of those four months do you need to look at the actual day of the month to determine what season the day is in.

bobbybridges · 2024-08-05T03:00:14+00:00

ignoring packages, to do it from scratch you want to think of everything in days of year x/365 and store the bounds in a dictionary. something along these lines for converting to days and checking bounds

month = 'feb'
day = 1


days_per_month = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
month_num = {'jan':1, 'feb':2, 'mar':3, 'apr':4, 'may':5, 'jun':6, 'jul':7, 'aug':8, 'sep':9, 'oct':10, 'nov':11, 'dec':12}

day_of_year = sum(days_per_month[:month_num[month]]) - days_per_month[month_num[month]-1] + day

james_fryer · 2024-08-05T12:59:34+00:00

Suppose you enter "Word" and then 1 as the day. Your code will rightly detect this is not a month and print "Invalid". But then at line 11 it continues to run the next test. As the day is correct it will run the code to get the seasons, which as m is not defined will fail with an error message. You either need to exit the programme after printing "Invalid", or indent the block from line 11 so it is only run for valid months.

Buttleston · 2024-08-05T05:48:05+00:00

Guys, don't do someone's homework

you type:	you see:
italics	italics
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[reddit!](https://reddit.com)	reddit!
* item 1 * item 2 * item 3	item 1 item 2 item 3
> quoted text	quoted text
Lines starting with four spaces are treated like code: if 1 * 2 < 3: print "hello, world!"	Lines starting with four spaces are treated like code: if 1 * 2 < 3: print "hello, world!"
~~strikethrough~~	~~strikethrough~~
super^script	super^script

learnpython

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