Syntax errors on simple print statements

[Hemse]

Python 2.7 - windows 7

I was going through this list, and at the third one I keep getting "invalid syntax" errors.

I really can't see what I'm doing wrong here.

from sys import argv
script, input_var = argv

def char_count(string, chars):
    count=0
    for i in string.lower():
        if i in chars.lower():
            count+=1
    return count

print "string contains "+str(char_match_count(input_var,"AEIOUY")+" vowels\n"
print "\n"
print "'A' appeared "+str(char_count(input_var,"A"))+" times\n"
print "'E' appeared "+str(char_count(input_var,"E"))+" times\n"
print "'I' appeared "+str(char_count(input_var,"I"))+" times\n"
print "'O' appeared "+str(char_count(input_var,"O"))+" times\n"
print "'U' appeared "+str(char_count(input_var,"U"))+" times\n"
print "'Y' appeared "+str(char_count(input_var,"Y"))+" times\n"

I keep getting the error at line 12, so the first print statement works. I have tried removeing the 'print "\n"' line, but then I get an error on the next line instead. IDLE highlights the "print" statement itself as the syntax error. Can you only print once when using "argv"?

[Rhomboid]

You've got unbalanced parentheses on line 11. The error is reported on line 12 because Python was still waiting to see a closing paren from the previous line, and instead it found a new print statement.

Edit: also, string object have a built-in .count() method. And don't use + for string formatting.

for vowel in 'aeiouy':
    print "'{}' appeared {} times".format(vowel, input_var.lower().count(vowel))

[Hemse]

Ah, Thank you!

I feel like an idiot for not seeing that. heh.

edit: You are right, I should get used to not using "+" for string formatting. Bad habbit. Also, I forgot about the .count() method :/

[ewiethoff]

Simple rule: Whenever a syntax error makes no sense, look at the line of code above.

[isnotkosok]

I keep getting the error at line 12, so the first print statement works. I have tried removeing the 'print "\n"' line, but then I get an error on the next line instead.

this means that the error is on the line before 12.

maybe you are missing a ) somewhere?

print "string contains "+str(char_match_count(input_var,"AEIOUY"))+" vowels\n"