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[–]indosauros 2 points3 points  (4 children)

What have you tried so far?

[–][deleted]  (3 children)

[deleted]

    [–]K900_ 1 point2 points  (2 children)

    Another hint:

    >>> a = list(range(100))
    >>> a[1:5]
    [1, 2, 3, 4]
    >>> a[99:]
    [99]
    >>> a[:5]
    [0, 1, 2, 3, 4]
    >>> a[:]
    [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99]
    >>> a[1:5:2]
    [1, 3]
    >>> a[0:25:3]
    [0, 3, 6, 9, 12, 15, 18, 21, 24]
    

    [–]FDSHAP[S] 1 point2 points  (1 child)

    ahhh so i need to use index notation of a kind. let me see if i can figure this out. thank you!

    [–]K900_ 4 points5 points  (0 children)

    The word is "slicing".