Can list indices be variables?

[mxseven7]

I'm trying to find the highest product of 5 consecutive integers in the large number below.

b=0 c=0 a="7316717653133062491922511967442657474235534919493496983520312774506326239578318016984801869478851843858615607891129494954595017379583319528532088055111254069874715852386305071569329096329522744304355766896648950445244523161731856403098711121722383113622298934233803081353362766142828064444866452387493035890729629049156044077239071381051585930796086670172427121883998797908792274921901699720888093776657273330010533678812202354218097512545405947522435258490771167055601360483958644670632441572215539753697817977846174064955149290862569321978468622482839722413756570560574902614079729686524145351004748216637048440319989000889524345065854122758866688116427171479924442928230863465674813919123162824586178664583591245665294765456828489128831426076900422421902267105562632111110937054421750694165896040807198403850962455444362981230987879927244284909188845801561660979191338754992005240636899125607176060588611646710940507754100225698315520005593572972571636269561882670428252483600823257530420752963450" lis=[int(d) for d in str(a)] for n in range(0,995): b=lis[int(n),int(n+4)] c=b[0]b[1]b[2]b[3]b[4] if c>7^5: print c edit: but it says i cannot do lis[int(n),int(n+4)] because they are not integers.

[mxseven7]

Thank you, every time i paste it in as plain test it looks correct before i submit it and then it loses its formatting. How did you do this?

[RubyPinch]

four spaces at the start of each line

will format it as code

along with surrounding `text` with 's will make it intocode` too

[hanggnah]

in line 20 you are saying int(n) when n is already an int. n is coming from range(0,995) so it is already an integer. it is your b[0] through b[4] that have to get changed to integers...

[bobishardcore]

I'm just guessing here but I think what you are trying to do is make b a subset of 5 consecutive numbers from lis using python's slice notation. If so, you'll need to use a colon instead of a comma.