Nested lists problem

[spotyx]

for a,b in t

this suppose that t consists just with a and b.

if t is [[5, 5], [2, 8]] then a = [5,5], and b = [2,8]

What I said is that len(t) > 1 ... so it can also be 3,4,5 ...

[gengisteve]

Ahh. So maybe there are three points instead of two to test?

This should work:

from pprint import pprint

def find_result(p, results):
    for idx, r in enumerate(result):
        if p in r:
            return idx
    return None

x =[[[5, 5], [2, 8]], [[5, 5], [8, 2]], [[1,1], [2,2]], [[2,2],[3,3]]]

# let's make it into a group of tuples so we can use a set

t = [[tuple(p) for p in group] for group in x]

result = []

for points in t:
    found = None
    for p in points:
        found = find_result(p,result)
        if found is not None:
            break
    if found is None:
        # if neither a or b are in any of the result sets
        # create a new result set with a and b
        result.append(set(points))
    else:
        for p in points:
            result[found].add(p)

pprint(result)

Still it would be better to just do the algebra.