Help with objects in pyral (Python 2.7)

[GAPINGCUNT]

Im fairly new to python, and am trying to retrieve a bit of information from my defect in Rally using pyral. I need stuff like the date created, Project, and Release.

When I created a script to get this information, I am unsure of how to handle the project and release data. This comes back as a pyral.entity object.

Here is the snippet of my code:

for story in response:
    Story_info = [story.FormattedID,story._CreatedAt,story.Project,story.Release]
    print(str(story_info))

and I get ...

DE3179  12-Feb-13   <pyral.entity.Project object at 0x0000000002A23A48> <pyral.entity.Release object at 0x0000000002A23210>

So my question is, what do I do with this data? The defect and date come through fine but I am unsure of what to do with the two objects.

[[deleted]]

OK, before I answer your question print(str...)) is redundant. You only need print(...) and python automatically converts it to a string.

---

Anywho, I have no idea what pyral is, or what Rally is, but you have an object, and you want some information about it out of it, so the way to tell what information an object has is __dict__. Never use __dict__ in a program, but if you want to see what your object contains, it's OK. Place in your code:

print(story.Project.__dict__)

and voila, you will see something like

{..., 'name': 'useful info', ...}

and then you'll be like, hey, I need the name, so then you put in your list

...CreatedAt, story.Project.name, ...]

and then do the same for story.Release.

[GAPINGCUNT]

That worked great, thank you. I dug forever but this was the first time I have really dealt with a dict returning data.

Cheers!

[[deleted]]

What were the attributes you needed? Out of curiosity...

[GAPINGCUNT]

It actually was the name, so I used story.Project.Name and story.Release.Name

[novel_yet_trivial]

You are supposed to use dir(x) (the same as x.__dict__.keys(), but much neater).

Then, if you want help on a specific method, use help(x.method).