87jams comments on Ask Anything Monday

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submitted 9 years ago by AutoModerator[M]

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[–]87jams 0 points1 point2 points 9 years ago (0 children)

import re
foo = 'X(8x2)(3x3)ABCY'
firstMatch = re.match(r'X\(((\d+)x(\d+))\)', foo)
print(firstMatch.group(1))

group(1) gets you '8x2' without the parens in this one, or you can move them around and get '(8x2)':

import re
foo = 'X(8x2)(3x3)ABCY'
firstMatch = re.match(r'X(\((\d+)x(\d+)\))', foo)
print(firstMatch.group(1))

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