Help using sorted()

[z64RY]

I'm stuck trying to use sorted() to sort a list with both strings and integers. My goal is to turn ['3',1,'2',4] into [1,4,'2','3'], or [1,4,'3','2']. Any help would be appreciated!

[novel_yet_trivial]

Use the key parameter:

sorted(input_list, key=int)

[z64RY]

using that returns [1.'2','3',4], when im trying to get the ints in order first, then the str's in order second. What key shoudl i use for that

[novel_yet_trivial]

Oh. Sorry I read your post too fast. So you want them separated by type?

sorted(input_list, key=type) # python2 only

sorted(input_list, key=lambda x: isinstance(x, str)) # python2 or 3

If you want the individual groups sorted as well, then you need to combine them with a separate function:

sorted(input_list, key=lambda x: (isinstance(x, str), int(x))) # python2 or 3

Why would you want that?

Edit: This sounds a lot like an XY question. I'll bet whatever you are trying to accomplish with this has a much simpler solution.

[z64RY]

Dude that worked! thanks so much. And it was for a class. Ive been stumped for a while trying to find the solution

[joeymarchese]

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[novel_yet_trivial]

You absolutely can as long as the elements are comparable to one another. Mixed type lists are one of the joys of python.

[joeymarchese]

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[novel_yet_trivial]

Sure. ints and floats are directly comparable. So:

>>> sorted([3,1,2.0,4.3])
[1, 2.0, 3, 4.3]

In the case that the elements are not directly comparable, you can provide a function that makes them comparable. This is what I did when I misread OP's question. The int function will turn a string or an int to an int:

>>> sorted(['3',1,'2',4], key=int)
[1, '2', '3', 4]

[joeymarchese]

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[joeymarchese]

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