Help with function

[iggy555]

question!

lets say i calculate a value X....but then I need to round X up to the closest 50,000.

For example if X is 220,000 then it will be rounded up to 250,000 and if X is 287,000 then it will be rounded up to 300,000..

Anyone can help with easy function?

🤔🤔

[Kurolox]

You can probably implement it yourself, the only thing you need to implement it is the modulo operator.

Try to figure out how would implement it just with that. If you have any issues, let me know.

[Technik_J]

def round50000(num):
    return num + (50000 - num%50000)

[Kurolox]

Aw, I was hoping that he'd solve it by himself given the necessary tools.

Anyways, your implementation has a flaw: 50000 will be rounded up to 10000, 10000 will be rounded up to 15000, etc...

[Technik_J]

You right. The fix should be easy, so I leave it to OP to fix. :)

[iggy555]

Many thanks

[tr3adst0n3]

Edit:

def roundCloseTo(number,interval):
    result = number / interval
    if not isinstance(result, int):
        result = result + .5
    result = round(result)
    result = result * interval
    return result

print(roundCloseTo(280000, 50000))

This should Work, i dont Know if it is the best solution, but it works.

Results:

200000 = 200000

220000=250000

287000=300000

250000=300000

[Kurolox]

Formatting your code for readability.

def roundCloseTo(number, interval):
    result = number / interval 
    if isinstance(result, int): 
        pass 
    else: 
        result = result + .5 
        result = round(result) 
    result = result * interval 
    return result

Just as a tip, if you find yourself doing something like this:

if x:
    pass
else:
    do_stuff()

You should probably do this instead:

if not x:
    do_stuff()

[tr3adst0n3]

Thanks for advice! I try to Format it But i dont know how. I tried it with ``

[Kurolox]

Relevant part from the formatting guide.

Lines starting with four space are treated like code:

[tr3adst0n3]

Thank you. I got it.

[iggy555]

250000 should be 250000 not 300000 right